David Niklas
2018-08-15 23:48:47 UTC
On Thu, 9 Aug 2018 15:57:32 +0200 (CEST)
{
printf "Yes.\n\n"
}
Yes.
export base="https://curl.haxx.se" # Base url.
export in2="download.html" # New part. Notice that the / is missing.
export in3="#Win64" # Something I added.
curl --append-urls $base $in2 $in3
Or
curl --base-url $base $in2 $in3
you want to change hosts? Your example makes no sense to me.
export in1="../download.html"
for i in DragonFlyBSD FreeBSD NetBSD; do
curl --base-url $base --output-url - $in1 "#" $i | ./download_curl.sh
done
As an award for your work on curl I award you, the extra
large virtual happy face.
<@ @>
v
Sorry, I don't have anything more exiting...
David
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Hi,
In a future libcurl release, there is going to be a URL
parsing/handling API [1] added. It can parse URLs, allow access to
parts of the URL, setting or updating specific parts and can "merge" a
relative URL onto an absolute one.
Cool.In a future libcurl release, there is going to be a URL
parsing/handling API [1] added. It can parse URLs, allow access to
parts of the URL, setting or updating specific parts and can "merge" a
relative URL onto an absolute one.
Do you think the command line tool would benefit from offering these
services somehow? If so, how? Would you like curl to help your scripts
or shells with in this regard?
if(( want_shell || want_script ) && IN_LATEST_COOL_CURL_VERSION)services somehow? If so, how? Would you like curl to help your scripts
or shells with in this regard?
{
printf "Yes.\n\n"
}
Yes.
Extract the different parts from a URL? Maybe like this?
in="https://example.com/index.html"
curl --url-input $in --url-out "%{host} %{path}\n"
Or like this:in="https://example.com/index.html"
curl --url-input $in --url-out "%{host} %{path}\n"
export base="https://curl.haxx.se" # Base url.
export in2="download.html" # New part. Notice that the / is missing.
export in3="#Win64" # Something I added.
curl --append-urls $base $in2 $in3
Or
curl --base-url $base $in2 $in3
Maybe change parts of a URL and output the new version?
curl --url-input $in --url-replace "host=example.org" --url-out
"%{url}\n"
Please try something more real world (even contrived). Why wouldcurl --url-input $in --url-replace "host=example.org" --url-out
"%{url}\n"
you want to change hosts? Your example makes no sense to me.
Perhaps applying a relative path onto an absolute URL and show the
resulting path part?
curl --url-input $in --url-new "../index?nooo" --url-out "%{path}\n"
<snip>resulting path part?
curl --url-input $in --url-new "../index?nooo" --url-out "%{path}\n"
export in1="../download.html"
for i in DragonFlyBSD FreeBSD NetBSD; do
curl --base-url $base --output-url - $in1 "#" $i | ./download_curl.sh
done
As an award for your work on curl I award you, the extra
large virtual happy face.
<@ @>
v
Sorry, I don't have anything more exiting...
David
-----------------------------------------------------------
Unsubscribe: https://cool.haxx.se/list/listinfo/curl-users
Etiquette: https://curl.haxx